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25x^2=8-35x
We move all terms to the left:
25x^2-(8-35x)=0
We add all the numbers together, and all the variables
25x^2-(-35x+8)=0
We get rid of parentheses
25x^2+35x-8=0
a = 25; b = 35; c = -8;
Δ = b2-4ac
Δ = 352-4·25·(-8)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-45}{2*25}=\frac{-80}{50} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+45}{2*25}=\frac{10}{50} =1/5 $
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